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The rst simulation in Fig. 3.14 showed the results of the simulation without DC current. As you can see, the inrush current is considerably higher than the value we expected in the rst simulation. This is due to the saturation of the inductors. The waveforms in Fig. 3.14 show the inductance during the inrush current. The input inductor is almost completely saturated by the inrush current. The inductance value in the schematic is somewhat higher than the design value. The second simulation in Figs. 3.16 and 3.17 shows the results of the simulation with a DC value of 4.5 A added to the current source I1. The current is negative because of the direction of the current source. The inductor values are almost identical to the design values. The inrush current analysis has not been performed, because it is unrealistic

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And remember, the clients could be either local or remote (in other words, on the same machine as the database or on a machine somewhere else on the network), so you ll have to think of issues related to both of those scenarios. Locking is crucial, but fortunately the Developer exam isn t asking you to implement a complete distributed transaction system using the two-phase commit protocol. In fact, this is much simpler than transactions, but it will require you to understand the fundamental issues surrounding concurrent access to data. Remember the bank account example from 9 The one where the husband and wife both shared the same account If you re not absolutely clear about how to handle synchronization, then reread that chapter. In order to correctly implement your locking strategy, you re going to need a solid grasp on synchronization, wait(), notify(), and notifyAll(). So, ready for some questions Once again, these are in no particular order.

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We then have that " horizontal component of E1 103:448 cos 21:80148 96:0491 " vertical component of E1 103:448 sin 21:80148 38:4196 " Next, let q2 2 10 6 coulombs at the point x 24, and let E2 be the eld strength at the point (15, 6) due to q2 . Setting q q2 2 10 6 and r2 117 in eq. (6) gives " E2 153:846= 33:69018 in which there is a force of attraction between q0 and q2 and thus the force vector acting on q0 points toward q2 , resulting in a negative value of relative to the x-axis, as can be seen from inspection of the gure. We then have that " horizontal component of E2 153:846 cos 33:69018 128:0076 " vertical component of E2 153:846 sin 33:69018 85:3385 " Now, letting E be the resultant eld strength at the point (15, 6), we have " horizontal component of E 96:0491 128:0076 224:0567 " vertical component of E 38:4196 85:3385 46:9189 Therefore, " E hence, " E 228:917= 11:8278 newtons=coulomb; answer shown graphically in the following diagram. p arctan 46:9189=224:0567 52402:79=

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4. Assign the string retrieved from the array to the declared instance variable name. We could have made it much easier to read if we d just written String[] nameList = {"Fluffy", "Fido", "Rover", "Spike", "Gigi"}; String name = nameList[x];

3. From eq. (8), qV W joules, answer. 4. By eq. (8), V W 2:65 339:74 volts; answer: q 0:0078

But where s the fun in that Throwing in unusual syntax (especially for code wholly unrelated to the real question) is in the spirit of the exam. Don t be startled! (OK, be startled, but then just say to yourself, Whoa and get on with it.)

We re invoking the no-arg version of the constructor (causing a random name from the list to be selected and passed to the other constructor). We re invoking the overloaded constructor that takes a string representing the name.

5. The answer is no, because, in order to calculate the potential di erence between a and b, the eld strength must be known at ALL POINTS along any path connecting a and b and NOT at just the end points of the path. (Such calculations, however, need not concern us here, because potential di erence is normally a known quantity in practical work.)

Attenuation in dB (Amps)

The key point to get from this code example is in line 8. Rather than calling super(), we re calling this(), and this() always means a call to another constructor in the same class. OK, fine, but what happens after the call to this() Sooner or later the super() constructor gets called, right Yes indeed. A call to this() just means you re delaying the inevitable. Some constructor, somewhere, must make the call to super(). Key Rule: The first line in a constructor must be a call to super() or a call to this(). No exceptions. If you have neither of those calls in your constructor, the compiler will insert the no-arg call to super(). In other words, if constructor A() has a call to this(), the compiler knows that constructor A() will not be the one to invoke super().

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