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The preceding rule means a constructor can never have both a call to super() and a call to this(). Because each of those calls must be the very first statement in a constructor, you can t legally use both in the same constructor. That also means the compiler will not put a call to super() in any constructor that has a call to this().

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" More basically, the equation for E must be given before the potential di erence between two points can be calculated. This is of little importance, however, because potential di erence is generally the known quantity in practical work. 6. If n number of electrons, then n 1:602 10 19 1 (1 coulomb), and thus n 1 1019 6:24 1018 electrons; answer: 19 1:602 1:602 10

class A { A() {

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7. In eq. (9), for this problem, Dq 9 106 1:602 10 19 1:44 10 12 coulombs; and Dt 10 7 seconds; thus Dq 1:44 10 12 1:44 10 5 amperes; answer; or Dt 10 7 14:4 microamperes; answer: 8. By eq. (11), I 48=6 8 amperes, answer. 9. By eq. (15), 48 8 384 watts, answer. By eq. (16), (48)2 6 384 watts, answer. By eq. (17), (8)2(6) = 384 watts, answer. 10. By eq. (17), I p p P=R 18=75 0:4899 amperes, answer.

Constructors and Instantiation (Exam Objectives 1.3, 6.3, 6.2)

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this("foo"); } A(String s) { this(); } }

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11. By eq. (17), P 1:86 2 25 86:49 watts 86:49 joules per second, and therefore 86.49/4.186=20.6617 calories/second, answer. 12. The problem is to calculate the values to put into eq. (18), beginning with the length L, as follows. Manipulating units like algebraic quantities (as discussed just prior to problem 3 in Chap. 1), and noting that 1 foot 12 inches and 1 meter 39:370 inches, we have, for the value of L L 450 feet Next, the radius is 0:25 inch hence, A 6:35 2 10 6 1:2668 10 4 square meters Next, noting that for this problem T 868F 308C; we have, using eq. (19), 2:83 10 8 1 4:03 10 3 10 2:94405 10 8 Upon substituting the above values of L, A, and into eq. (18) you should nd that R 0:03188 ohms, answer. 13. Note that only the temperature T is to change in this problem. Let R1 and 1 be the values at T1 , and R2 and 2 be the values at T2 . Then, by eq. (18), 0:25 inch 1 meter 6:35 10 3 meters; 39:370 inches 450 feet 12 inches 1 meter 137:160 meters 1 foot 39:370 inches

Your compiler may not actually catch the problem (it varies depending on your compiler, but most won t catch the problem). It assumes you know what you re doing. Can you spot the flaw Given that a super constructor must always be called, where would the call to super() go Remember, the compiler won t put in a default constructor if you ve already got one or more constructors in your class. And when the compiler doesn t put in a default constructor, it still inserts a call to super() in any constructor that doesn t explicitly have a call to the super constructor unless, that is, the constructor already has a call to this(). So in the preceding code, where can super() go The only two constructors in the class both have calls to this(), and in fact you ll get exactly what you d get if you typed the following method code:

public void go() { doStuff(); } public void doStuff() { go(); }

R1 1 L=A and R2 2 L=A from which, after dividing the second equation by the rst, we have R2 2 = 1 R1 Hence, using eq. (19), R2 from which you should nd that R2 1:076 2:625 2:721 ohms; answer: 1:038 ! 1 0 T2 20 R 1 0 T1 20 1

Now can you see the problem Of course you can. The stack explodes! It gets higher and higher and higher until it just bursts open and method code goes spilling out, oozing out of the JVM right onto the floor. Two overloaded constructors both calling this() are two constructors calling each other. Over and over and over, resulting in

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14. By eq. (19), 49 10 8 1:00545 49:2671 10 8 . Then, from eq. 18, L RA 35 25 10 8 55:7957 meters 183:056 feet; answer: 49:2671 10 8

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