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Cross 1 2 3 4 5 6 Recipient ara-1 ara-2 ara-1 ara-3 ara-2 ara-3 Donor ara-2 ara-1 ara-3 ara-1 ara-3 ara-2 Ratio: thr ara leu thr ara leu 48.5 2.4 4.0 19.1 1.5 25.5

Known Quantities: Microcomputer output resistance and output signal voltage and current levels; LED offset voltage, required current, and power rating; BJT current gain and base-emitter junction offset voltage Find: Collector resistance, RC , such that the transistor is in the saturation region when the computer outputs 5 V; power dissipated by LED Schematics, Diagrams, Circuits, and Given Data:

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32. De ne and illustrate specialized and generalized transduction. 33. In E. coli, the three loci ara, leu, and ilvH are within 1/2-minute map distance apart. To determine the exact order and relative distance, the prototroph (ara leu ilvH ) was infected with transducing phage P1. The lysate was used to infect the auxotroph (ara leu ilvH ).The ara classes of transductants were selected to produce the following data:

= 95

Microcomputer: output resistance = RB = 1 k ; Von = 5 V; VOFF = 0 V; I = 5 mA Transistor: VCC = 5 V; V = 07 V; = 95 LED: V LED = 14 V; ILED > 15 mA; Pmax = 100 mW

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35. An E. coli strain that is leu thr azir is used as a donor in a transduction of a strain that is leu thr azis. Either leu or thr transductants are selected and then scored for unselected markers. The results are obtained:

Assumptions: Use the large-signal model of Figure 922 Analysis: When the computer output voltage is zero, the BJT is clearly in the cutoff

4000 5000 7000 8000

region, since no base current can ow When the computer output voltage is VON = 5 V, we wish to drive the transistor into the saturation region Recall that operation in saturation corresponds to small values of collector-emitter voltages, with typical values of VCE around 02 V Figure 925(a) depicts the equivalent base-emitter circuit when the computer output voltage is VON = 5 V Figure 925(b) depicts the collector circuit, and Figure 925(c), the same collector circuit with the large-signal model for the transistor (the battery VCEsat ) in place of the BJT From this saturation model we write: VCC = RC IC + V LED + VCEsat

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Outline the speci c techniques used to isolate the various transduced classes. What is the gene order and what are the relative cotransduction frequencies between genes Why do some classes occur so infrequently

425

1. Consider the data from table 7.4. Is there another way to interpret the data other than coming from a circular bacterial chromosome

1,000

+ 5V _

3480 3500

2. Why might transformation have evolved, given that the bacterium is importing DNA from a dead organism

Figure 925 (a) BE circuit for LED driver; (b) Equivalent collector circuit of LED driver, assuming that the BJT is in the linear active region; (c) LED driver equivalent collector circuit, assuming that the BJT is in the saturation region

Suggested Readings for chapter 7 are on page B-4.

We know that the LED requires at least 15 mA to be on; let us suppose that 30 mA is a reasonable LED current to ensure good brightness, then the value of collector resistance that would complete our design is, approximately, RC = 113 With the above design, the BJT LED driver will clearly operate as intended to turn the LED on and off But how do we know that the BJT is in fact in the saturation region Recall that the major difference between operation in the active and saturation regions is that in the active region the transistor displays a nearly constant current gain, , while in the saturation region the current gain is much smaller Since we know that the nominal for the transistor is 95, we can calculate the base current using the equivalent base circuit of Figure 925(a) and determine the ratio of base to collector current: IB = VON V 43 = 43 mA = RB 1,000 Thus, it can

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The actual large-signal current gain is therefore equal to 30/43 = 67 be reasonably assumed that the BJT is operating in saturation We nally compute the LED power dissipation: PLED = V LED IC = 14 03 = 42 mW < 100 mW

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